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Density-kernel derivatives

The total energy depends upon $K^{\alpha \beta}$ both explicitly and through the electronic density $n({\bf r})$. We use the result

\begin{displaymath}
\frac{\partial K^{ij}}{\partial K^{\alpha \beta}} = \delta_{\alpha}^i
\delta_{\beta}^j .
\end{displaymath} (7.20)



Subsections

Peter D. Haynes
1999-09-21