Density-kernel derivatives

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The total energy depends upon $K^{\alpha \beta}$ both explicitly and through the electronic density $n({\bf r})$ . We use the result

$\begin{displaymath} \frac{\partial K^{ij}}{\partial K^{\alpha \beta}} = \delta_{\alpha}^i \delta_{\beta}^j . \end{displaymath}$

(7.20)

Peter D. Haynes
1999-09-21