...size',

The step size is chosen so that the acceptance ratio () is approximately 16#16, as this has been shown [3] to give the maximum computational efficiency.

...determinants

It can be shown that as the Hamiltonian does not include spin coordinates, the expectation value of the energy is the same when using () as when using a full Slater determinant in the trial wavefunction.

Andrew Williamson
Mon May 22 14:48:37 BST 1995