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Hartree and exchange-correlation energies
Again this gradient is derived by considering the change in the electronic density.
(7.34)
Therefore
(7.35)
Peter D. Haynes
1999-09-21
![\begin{displaymath}
\frac{\partial n({\bf r'})}{\partial \phi_{\alpha}({\bf r})}...
..._i({\bf r'}) \delta({\bf r} - {\bf r'}) K^{i \alpha} \biggr] .
\end{displaymath}](img988.gif)
